**Contents**show

In this article, you will learn the calculation process to find total bricks required for a room.

**Calculation process to find bricks required for a room**

### A) **Calculate the size of Room**

Generally, the standard size of the room is 12 feet long, 10 feet breadth and 10 feet in height.

**And the width of the brick walls is 9 inches.**

Length of walls of a room (L) = 12 ft x 2 + 10 ft x 2 = 44 ft

Total Length and breadth of walls of room = 44 ft

Breadth of brick wall (B) = 9″ = 0.75 ft

Height of the room(D) = 10 ft

**Volume of brick-work = Length x width x Thickness of wall**

= 44*.75*10

= 330 cubic ft =9.345 m³

Deduction of Door = L x B x D = 3 x 7 x 0.65 = ‐13.65 cubic feet

Deduction of Door Lintel = L x B x D = 3.4 x 0.4 x 0.65 = ‐0.884 cubic feet

Total Volume of brick work after deductions = 330 ‐ 13.65 – 0.884 = 315.466 cubic feet

**Assuming:-**

- Brick size = 9” x 4.5” x 4” = 0.09375 cubic feet
- Thickness of mortar = 0.328 ft (10 mm)

### B) **Calculate total Bricks required for room**

**No. of bricks = Volume of brick-work / volume of 1 brick with mortar**

= 315.466/0.1089

∴ No. of bricks = 2897 bricks

Volume of 1 Brick with mortar = 9.3937”× 4.8937” × 4.09375” = 188.189 cubic inch = 0.1089 cubic feet

**Total Volume of brick:-**

Volume of total no.of bricks = brick size in cubic feet x no. of bricks

= 0.09375 cubic feet * 2897 = 271.594

**Quantity of mortar = Volume of brick-work with mortar – Volume of bricks**

Quantity of mortar = 315.446 – 271.594 = 43.85 cubic feet

**Mix Ratio of cement-sand –> 1:6**

**Dry volume of mortar = Wet volume x 1.53**

∴ Dry volume of mortar = 43.85 cubic feet x 1.53

= 67.09 cubic feet

**C) Calculate Quantity of cement** **required** **for room**

**Quantity of Cement = Dry Volume of mortar x Cement ratio/Sum of the ratio of mortar**

∴Quantity of cement = (67.09 x 1) /(1+6)

= 9.584 cubic feet

**Density of Cement = 1440 kg/m³ =40.807kg/cubic feet**

∴ Weight of Cement = 40.807 x 9.584

= 391 Kg

**1 bag of cement contains 50 kg of cement**∴ Number of bags = 391 Kg / 50 k

= **7.82 No’s of bag**

**D) Calculate** **Quantity of Sand** **required for a room**

**Cement : Sand :: 1:6**

**Quantity of Sand = Quantity of Cement x 6**

∴ Quantity of Sand = 9.584 cubic feet x 6

**= 57.504 cubic feet**

In this way, you can find total bricks required for a room.

**You may also love to read: **Calculation process to find the quantity of cement sand for plastering.

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