How to calculate total bricks required for a room?

Number of bricks required for house construction

In this article, you will learn the calculation process to find total bricks required for a room.

Calculation process to find bricks required for a room

A) Calculate the size of Room

Generally, the standard size of the room is 12 feet long, 10 feet breadth and 10 feet in height.

And the width of the brick walls is 9 inches.

Length of walls of a room (L) = 12 ft x 2 + 10 ft x 2 = 44 ft
Total Length and breadth of walls of room = 44 ft
Breadth of brick wall (B) = 9″ = 0.75 ft
Height of the room(D) = 10 ft

Volume of brick-work = Length x width x Thickness of wall

= 44*.75*10

= 330 cubic ft =9.345 m³

Deduction of Door = L x B x D = 3 x 7 x 0.65 = ‐13.65 cubic feet
Deduction of Door Lintel = L x B x D = 3.4 x 0.4 x 0.65 = ‐0.884 cubic feet

Total Volume of brick work after deductions = 330 ‐ 13.65 – 0.884 = 315.466 cubic feet

Assuming:-

  1. Brick size = 9” x 4.5” x 4” = 0.09375 cubic feet
  2. Thickness of mortar = 0.328 ft (10 mm)

B) Calculate total Bricks required for room

No. of bricks = Volume of brick-work / volume of 1 brick with mortar

= 315.466/0.1089

∴ No. of bricks = 2897 bricks

Volume of 1 Brick with mortar = 9.3937”× 4.8937” × 4.09375” = 188.189 cubic inch = 0.1089 cubic feet

Total Volume of brick:-

Volume of total no.of bricks = brick size in cubic feet x no. of bricks

= 0.09375 cubic feet * 2897 = 271.594

Quantity of mortar = Volume of brick-work with mortar – Volume of bricks

Quantity of mortar = 315.446 – 271.594 = 43.85 cubic feet

Mix Ratio of cement-sand –> 1:6

Dry volume of mortar = Wet volume x 1.53

∴ Dry volume of mortar = 43.85 cubic feet x 1.53

= 67.09 cubic feet

C) Calculate Quantity of cement required for room

Quantity of Cement = Dry Volume of mortar x Cement ratio/Sum of the ratio of mortar

∴Quantity of cement = (67.09 x 1) /(1+6)

= 9.584 cubic feet

Density of Cement = 1440 kg/m³ =40.807kg/cubic feet

∴ Weight of Cement = 40.807 x 9.584

= 391 Kg

1 bag of cement contains 50 kg of cement∴ Number of bags = 391 Kg / 50 k

= 7.82 No’s of bag

D) Calculate Quantity of Sand required for a room

Cement : Sand :: 1:6

Quantity of Sand = Quantity of Cement x 6

∴ Quantity of Sand = 9.584 cubic feet x 6

= 57.504 cubic feet

In this way, you can find total bricks required for a room.

Number of bricks required for house construction

You may also love to read: Calculation process to find the quantity of cement sand for plastering.

Join our Facebook group: Engineering Knowledge

Sharing is caring. 😊😊

Recent Articles

Download NBC Codes: Nepal National Building Code (NBC)

Nationa Building Code (NBC Codes) is a group of 23 codes. At first 20 codes are developed after that 3 codes, architectural code, electrical,...

ETABS Shortcut keys !! Very Useful For ETABS

ETABS is engineering software used for structural analysis and design of buildings. In the engineering field mostly engineers prefer to work in ETABS because...

How to write a proposal for engineering projects?

The proposal is a written document designed or prepared to persuade a customer, company, government to –get the project, contract or tender win...

Report writing method for engineering projects !!!!

Report is an objective communication of factual information that serves for business purposes.Why we need to write a report?In professional life, you need to...

Highway Drainage: Effects & types of highway drainage

Highway Drainage is the process of interception and removal of water from over, under and the vicinity of the road surface. After the precipitation,...

Find us on

1,500FollowersFollow
14,937FollowersFollow
0SubscribersSubscribe

Leave A Reply

Please enter your comment!
Please enter your name here

Stay on op - Ge the daily news in your inbox